Some help please question below ?

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1 Answer
Al E.
May 24, 2018

If the data given is accurate, this is as simple as relating the molar enthalpy of reaction to the moles reacted.

#DeltaH_"rxn"^° = (-4163"kJ")/"mol"#

Hence, the heat released is,

#0.363"mol" * (-4163"kJ")/"mol" approx -1511"kJ"#

given your data.

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