How do you solve #8( 1+ 2v ) + 8= - 112#?

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Answer 1 · 2018-05-25T03:16:46

#v = -8#

Isolate your variable to find the value.

#8(1 + 2v) + 8 = -112#

#8(1 + 2v) = -120#

#1 + 2v = -15#

#2v = -16#

#v = -8#

Check: #8(1 + 2 * -8) + 8 = -112#

#8 * -15 + 8 = -112#

#-120 + 8 = -112#

#-112 = -112#