Why is the charge of Fe in the complex ion #"K"_4["Fe(C"_2"O"_4")"_3] color(white)(.) +2#?

1 Answer
Junaid Mirza
May 25, 2018

#"K"_4["Fe(C"_2"O"_4")"_3] -> 4"K"^+ + ["Fe(C"_2"O"_4")"_3]^(4-)#

Oxidation state of #"C"_2"O"_4^(2-)# is #-2#

In the complex ion #["Fe(C"_2"O"_4")"_3]^(4-)# let oxidation state of #"Fe"# be #x#. Then,

#x + (3 × -2) = -4#

#x - 6 = -4#

#x = +2#

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