How do you use synthetic substitution to find #P(x) = 4x^3-12x-2# for #x=5#?
1 Answer
May 26, 2018
#P(x=5)=438#
Explanation:
Given -
#P(x)=4x^3-12x-2#
#P(x=5)=4(5^3)-12(5)-2=500-60-2=438#
#P(x=5)=438#
