Question

Derivative of y with respect to x, y=|sinx|+|cosx| at x=2π/3 is ?

Answer 1

`(sqrt 3 - 1)/2`

Explanation:

`sin ((2 pi)/3) = sqrt3/2`

`cos ((2 pi)/3) =- 1/2`

`implies (d(|sinx|+|cosx|))/dx |_(x= sqrt3/2)`

`implies (d(sinx- cosx ))/dx`

`= cos x + sin x = (sqrt 3 - 1)/2`