#sin(alpha/2) = 1/4# and #405^@ < alpha/2 < 450^@#. Find #cosalpha#"?
Answer is #-(sqrt(8+2sqrt15))/4# .
Thanks in advance!
Answer is
Thanks in advance!
1 Answer
May 27, 2018
The interval
Calculator gives -->
The arc (a/2) isn't located in the above interval.
So the question should be corrected before solving.