Solve the following using logs? 7e^x-2 + 5 = 12.7

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Answer 1 · 2018-05-27T15:46:33

#x= ln(1.1) +2 ~~2.09531#

I am assuming this is your equation:

#7e^(x-2) + 5 = 12.7#

#7e^(x-2) = 7.7#

#e^(x-2) = 1.1#

#ln(e^(x-2)) = ln(1.1)#

#x-2 = ln(1.1)#

#x= ln(1.1) +2 ~~2.09531#