How do you solve the system of equations #2x + 8y = 10# and #2x + y = 17#?

2 Answers
May 27, 2018

#x=9#
#y=-1#

Explanation:

#2x + 8y = 10#
#2x + y = 17#

#2x + 8y = 10#
#-1(2x + y = 17)#

#2x + 8y = 10#
#-2x - y = -17#

now add the equations together:

#7y = -7#

#y=-1#

Use either of the 2 original equations with your #y# value to solve for #x#:

#2x + y = 17#

#2x + (-1) = 17#

#2x = 18#

#x=9#

May 27, 2018

The solution is #(9,-1)#.

Explanation:

#"Equation 1":# #2x+8y=10#

#"Equation 2":# #2x+y=17#

The solution to a system of linear equations is the point or points they have in common. I'm going to solve the system by elimination.

Multiply Equation 1 by #-1#. This will reverse the signs.

#-2x-8y=-10#

Add Equation 1 to Equation 2.

#color(white)(..)2x+color(white)(.)y=color(white)(..)17#
#-2x-8y=-10#
#-------------#
#color(white)(.......)-7y=color(white)(....)7#

Divide both sides by #-7#.

#y=-7/7#

#y=-1#

Substitute #-1# for #y# in Equation 2 and solve for #x#.

#2x-1=17#

Add #1# to both sides.

#2x=17+1#

#2x=18#

Divide both sides by #2#.

#x=18/2#

#x=9#

The solution is #(9,-1)#.

graph{(2x+8y-10)(2x+y-17)=0 [-4.25, 15.75, -5.04, 4.96]}