How do you solve #10^ { x } = 75#?

1 Answer
Jim G.
May 28, 2018

#x~~1.875" to 4 dec. places"#

Explanation:

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)logx^nhArrnlogx#

#"take log of both sides"#

#"note that "logx-=log_(10)x" and "log_(10)10=1#

#log10^x=log75#

#xlog10=log75#

#x=log75/log10=log75~~1.875#

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