How do you write #y=-3(x-2)^2+8# into standard form?

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Answer 1 · 2018-05-28T14:37:36

#color(indigo)(y = -3x^2 + 12x - 4#

#y = -3 * (x - 2)^2+8#

#y = -3 * (x^2 - 4x + 4)+8#, expanding.

#y = -3x^2 + 12x - 12+8#, removing bracket and multiplying.

#y = -3x^2 + 12x - 4#, final result.

Answer 2 · 2018-05-28T14:55:20

#y=-3x^2+12x-4#

#"expand "(x-2)^2=x^2-4x+4#

#y=-3(x^2-4x+4)+8#

#color(white)(y)=-3x^2+12x-12+8#

#color(white)(y)=-3x^2+12x-4larrcolor(blue)"in standard form"#