What is the standard form of #y= (x-6)(x-3)^2 #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Kalyanam S. May 28, 2018 #y = x^3 - 12x^2 + 45x - 54# is the standard form. Explanation: #y = (x-6) * (x-3)^2# #y = (x-6) * (x^2 -6x + 9)# #y = x^3 -6x^2 + 9x - 6x^2 + 36x - 54# #y = x^3 - 12x^2 + 45x - 54# is the standard form. Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1299 views around the world You can reuse this answer Creative Commons License