Question

When 435 J of heat is added to 3.40 g of olive oil at 21.0°C, the temperature increases by 85°C. What is the specific heat of the olive oil?

Answer 1

`"1.51 J/g°C"`

Explanation:

Specific heat (`"S"`) is given by the formula

`"S" = "Q"/"mΔT"`

Where

• `"Q ="` Heat added/released
• `"m ="` Mass of sample
• `"ΔT ="` Change in Temperature

`"S" = "435 J"/"3.40 g × 85°C" = "1.51 J/g°C"`