How do you find the center and radius for #(x - 9)^2 + (y + 11)^2 = 16#?
1 Answer
May 28, 2018
Explanation:
#"the standard form of the equation of a circle is"#
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"where "(a,b)" are the coordinates of the centre and r"#
#"is the radius"#
#(x-9)^2+(y+11)^2=16" is in standard form"#
#"with "(a,b)=(9,-(-11))" and "r=sqrt16#
#"centre "=(9,11)" and radius "=4#
