How do you solve the following linear system: # 2x+y=0, y = 4x - 3 #?

1 Answer
May 29, 2018

x=1/2 & y=-1

Explanation:

The way is very simple. Just eliminate one of the variable by substituting its value in the other equation.
#2x + y =0# ——— (i)
#y=4x-3# ——— (ii)

Using the value of ‘y’ from equation (ii), we have :-
#2x +(4x-3) =0#
i.e., #x=1/2#
Now put the value of x in any of the equations to get the value of y.

#:. x=1/2 and y=-1#

Hope it helps :)