A person travels the total distance in two parts in ratio 2:1 with a constant speed of 30km/h in the first part and 40km/h in the second part.What is average speed of the journey?
1 Answer
May 29, 2018
Given
Let
=>d_1=2k⇒d1=2k
andd_2=kd2=k
Total distance covered
Time taken to perform first part
Time taken to perform second part
Total time taken for journey
"Average speed"="Total distance"/"Total time taken"
=>"Average speed"=(3k)/((11k)/120)
=>"Average speed"=(3xx120)/(11)=32.bar72\ bb(kmh)^-1