How do you solve #4( 3+ 5x ) - 1= 31#?

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Answer 1 · 2018-05-30T09:03:52

#x=1#

#4(3+5x)−1=31#

Add 1 to both sides

#4(3+5x)=31+1#

Open bracket

#12+20x=32#

Subtract 12 from both sides.

#20x= 32-12#

#20x=20#

Divide both sides by 1

#(20x)/20 = 20/20#

#x =1#

Answer 2 · 2018-05-30T09:04:03

#x=1#

Firstly shift #-1# to the right
#4(3+5x)=31+1#
#4(3+5x)=32#

Then divide both sides by 4
#[4(3+5x)]/4=32/4#
#5x+3=8#

Shift #3# to the right
#5x=8-3#
#5x=5#

Then divide both sides by 5
#(5x)/5=5/5#
#x=1#