Question

How do you evaluate `f(x)=3lnx` for `x=0.75`?

Answer 1

`f(0.75) = -0.86 (2 dp)`

Explanation:

`f(x) = 3 ln x; x =0.75`

`f(0.75) = 3 ln 0.75;` or

`f(0.75) = 3 * (-0.28768);` or

`f(0.75) = -0.86 (2 dp)` [Ans]