How do you evaluate #log_3 3#?

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Answer 1 · 2018-05-30T15:27:26

#1#

We have
#log_3 3=x#

so

#3^x=3#
and we get
#x=1#

Answer 2 · 2018-05-30T15:46:42

#log_3 3=1#

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_b b=1#

#"thus "log_3 3=1#