How do you combine #(10+i0)/(1+i376.99)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Kalyanam S. May 31, 2018 #color(green)(=> (10 - i3769.9) / (1 + (376.99)^2)# Explanation: #(10 + i0) / (1 + i 376.99)# #i 0 = 0# #=> 10 / (1 + i 376.99)# Multiply and divide by #(1- i 376.99)# #(10 * (1 - i376.99)) / ((1 + i376.99)(1 - I 376.99))# #color(green)(=> (10 - i3769.9) / (1 + (376.99)^2)# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 1338 views around the world You can reuse this answer Creative Commons License