How do you find a standard form equation for the line with (-2, 1) and (2, 1)?
1 Answer
May 31, 2018
#y=1#
Explanation:
Given -
#(-2, 1); (2, 1)#
#x_1=-2#
#y_1=1#
#x_2=2#
#y_2=1#
#(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)#
#(y-1)=(1-1)/(2-(-2))(x-(-2))#
#y-1=0/(2+2)(x+2)#
#y-1=0/4(x+2)#
#y-1=0#
#y=1#