Question

What is the vertex of `3y= 2(x-7)^2 -5`?

Answer 1

Transform the function into vertex form, and match the values.

Explanation:

The vertex form is: `y = a(x-h)^2 + k`, where `(h,k)` is the location of the vertex.

To convert the original equation into this form, we can divide both sides of the equation by 3: `y = (2/3)(x-7)^2 - 5/3`

Reading from this equation we can see that `h = 7` and `k = -5/3`, and therefore the vertex is located at `(7,-5/3)`.