What is the solution to the following system?: −6x+10y=5,−2x+3y=−1

1 Answer
Bhavin B.
May 31, 2018

x=252

y=8

Explanation:

Make x or y the subject and then substitute that in one of the equation.

−6x+10y=5 -----> equation 1

−2x+3y=−1 ------> equation 2

Lets make x the subject in equation 1:

−6x+10y=5

−6x=5−10y

x=−56+106y ------> substitute x in equation 2

−2x+3y=−1 ------> equation 2

−2(−56+106y)+3y=−1

53−103y+3y=−1

3y−103y=−1−53

9y−10y3=−3−53

−13y=−83

y=−83×(−3)

y=8

Substitute y=8 in equation 2 to get value of y.

−2x+3y=−1 ------> equation 2
−2x+3(8)=−1

−2x+24=−1

−2x=−1−24

−2x=−25

x=252

Check the answer:

−6x+10y=5 -----> equation 1

−6(252)+10(8)=5-75+80 = 5# ----> correct

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