How do you solve the system of equations #y= 2- 6x# and #\frac { 1} { 2} y = x + 1#?

1 Answer
Jim G.
May 31, 2018

#(x,y)to(0,2)#

Explanation:

#y=2-6xto(1)#

#1/2y=x+1to(2)#

#"multiply both sides of equation "(2)" by 2"#

#y=2x+2to(3)#

#"equate equations "(1)" and "(3)#

#2x+2=2-6x#

#"add "6x" to both sides"#

#8x+2=2#

#"subtract 2 from both sides"#

#8x=0rArrx=0#

#"substitute "x=0" into equation "(3)#

#y=0+2=2#

#"the point of intersection "=(0,2)#
graph{(y-2+6x)(y-2x-2)=0 [-8.89, 8.89, -4.444, 4.445]}

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