How do you solve #-11< 2x - 1\leq 7#?
2 Answers
May 31, 2018
Explanation:
#"add 1 to each of the 3 intervals"#
#-11color(red)(+1)<2xcancel(-1)cancel(color(red)(+1))<=7color(red)(+1)#
#-10<2x<=8#
#"divide each interval by 2"#
#-5< x<=4#
#x in(-5,4]larrcolor(blue)"in interval notation"#
May 31, 2018
Explanation:
We can start by adding
Lastly, we can divide all three parts by
The key realization here is that we have three parts to the inequality, so we have to apply the operations to all three parts of it.
Hope this helps!