How do you solve #-19.2=-3.6r+2.4#?

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Answer 1 · 2018-05-31T20:16:47

#r = 6#

#-19.2 = -3.6r + 2.4#

Subtract #2.4# from both sides;

#-19.2 - 2.4 = -3.6r + 2.4 - 2.4#

#-19.2 - 2.4 = -3.6r+ 0#

#-19.2 - 2.4 = -3.6r#

#-21.6 = -3.6r#

Divide both sides by the coefficient of #r#

#(-21.6)/(-3.6) = (-3.6r)/(-3.6)#

#(-21.6)/(-3.6) = (cancel(-3.6)r)/cancel(-3.6)#

#(-21.6)/(-3.6) =r#

#6 = r#

#r = 6#