How do you solve #k/7+3-2k=-3#?

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Answer 1 · 2018-06-01T20:15:29

Combine like terms - this is a linear equation

Combine like terms - the two containing #k# and the two that are just numbers. This gives #(13k)/7=6#, so #k=42/13#.

Answer 2 · 2018-06-01T20:53:18

#k=42/13#

Re=arrange the terms with the variables on the left and the numbers on the right: (subtract #3# from both sides)

#k/7 -2k = -3-3#

#k/7 -2k =-6#

Multiply each term by #7# to get rid of the fraction.
#(cancel7xxk)/cancel7 -7xx2k = 7xx-6#

#k-14k = -42#

#-13k = -42" "larr div -13#

#k = 42/13#