#root(3)(20x^2y^7)*root(3)(50x^4y^2)# = ?

Question

A) #20^(1/3)(50^(1/3))x^(6)y^9#
B) #70^(1/3)x^(2)y^3#

C)#10x^(8/3)y^(14/3)#
D)#10x^2y^3#
E)#1000x^(8/3)y^(14/3)#

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Answer 1 · 2018-06-01T21:58:24

d) #10x^2y^3#

#=root(3)(20x^2y^7)*root(3)(50x^4y^2)#

#=root(3)((20x^2y^7)*(50x^4y^2))#

#=root3(1000x^6y^9)#

#=root3(10^3x^6y^9)#

#=10x^2y^3#