How do you solve #(-c+14)/5>8#?

1 Answer
EZ as pi
Jun 2, 2018

#c < -26#

Explanation:

Treat inequalities in the same way as an equation unless you multiply or divide by a negative number, in which case the inequality sign changes.

#(-c+14)/5 > 8#

#-c+14 > 40" "larr xx 5# on both sides

#-c > 40-14" "larr #subtract #14# from both sides

#-c color(red)(>) 26#

# c color(red)(<) -26" "larrdiv -1#

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