Question

In a right triangle ABC with angle A equal to 90o, find angle B and C so that sin(B) = cos(B). ?

Answer 1

B and C measures `90^@`

Explanation:

Let,
b be the length of the side opposite of the angle B
c the length of the side opposite of the angle C
h the length of the hypotenuse.

sin(B) = `b/h` and cos(B) =`c/h`

sin(B) = cos(B) means `b/h=c/h`

By cross multiplication,

`b=c`

This gives that the triangle is isosceles so,

B and C angle is equal to `45 ^@`