Two numbers are in the ration 4:3.If they differ by 18,find these numbers?

Question

Two numbers are in the ration 4:3.If they differ by 18,find these numbers?

1 Answer

Impact of this question

2474 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-02T16:31:48

Hence, the numbers are
$(x, y) \equiv (72, 54)$ $(x,y)-=(72,54)$

Explanation:

Let the two numbers be
$x and y$ $x and y$
$x : y = 4 : 3$ $x:y=4:3$
$\frac{x}{y} = \frac{4}{3}$ $x/y=4/3$
$4 y = 3 x$ $4y=3x$
$y = \frac{3}{4} x$ $y=3/4x$
$x - y = 18$ $x-y=18$
$x - \frac{3}{4} x = 18$ $x-3/4x=18$
$\frac{1}{4} x = 18$ $1/4x=18$
$x = 4 \times 18$ $x=4xx18$
$x = 72$ $x=72$
$y = \frac{3}{4} \times 72$ $y=3/4xx72$
$y = 54$ $y=54$

Hence, the numbers are
$(x, y) \equiv (72, 54)$ $(x,y)-=(72,54)$

Science

Math

Humanities

... and beyond

Two numbers are in the ration 4:3.If they differ by 18,find these numbers?

1 Answer

Explanation:

Related questions

Impact of this question