Let's do the classic long division method.
It helps to write down the first multiples of #21# to refer to
#21," "42," "63," "84," "105," "126," "147," "168," "189#
#color(white)(x..xx)color(red)(9)color(blue)(5)" "larrcolor(blue)(105) div 21 = color(blue)(5)#
#21|bar(color(red)(199)5)" "larr 19 div 21 = 0, " but "color(red)(199)div21= color(red)(9)#
#color(white)(xxx)color(red)(ul189)darr" "larr 21 xxcolor(red)(9)#
#color(white)(x..x)color(blue)(105)" "larr# subtract and bring down the #5#
#color(white)(x..x)color(blue)(ul105)" "larr21 xxcolor(blue)(5)#
#color(white)(xx.x.x)0" "larr# no remainder.