Question

Can someone help me solve this trigonometric equation problem step by step? Thank You!

Solve the equation within [0,2π][0,2π]. Write your solutions separated with commas. If no solutions exist, write no solution.

6sin(x−2)=14

Answer 1

This question `6sin(x-2) = 14` is wrong. Hence No Solution

Explanation:

Since, The value of `sinx` can only lie between [1,-1] for any value of `x in RR`.
i.e `-1<=sinx<=1` for every `x in RR`

so in the equation

`6sin(x-2) = 14`

`rArr sin(x-2) = 2.33`

and `2.33>1`

Therefore the question is wrong since the value of the `sin` can never be `2.33`.