How do you solve #\frac { 2x } { x - 4} = \frac { - x } { x - 8}#?

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Answer 1 · 2018-06-03T08:28:29

#x = 0 and 20/3#

As per the question, we have

#(2x)/(x-4)=(-x)/(x-8)#

#:. 2x(x-8)=(-x)(x-4)#

#:. 2x^2 - 16x = -x^2 + 4x#

#:. 2x^2+x^2 - 16x -4x = 0#

#:.3x^2 - 20x = 0#

#:. x(3x - 20) = 0#

#:. x = 0, 20/3#

Hence, the answer.