How do you solve \frac { 2x } { x - 4} = \frac { - x } { x - 8}?

1 Answer
Jun 3, 2018

x = 0 and 20/3

Explanation:

As per the question, we have

(2x)/(x-4)=(-x)/(x-8)

:. 2x(x-8)=(-x)(x-4)

:. 2x^2 - 16x = -x^2 + 4x

:. 2x^2+x^2 - 16x -4x = 0

:.3x^2 - 20x = 0

:. x(3x - 20) = 0

:. x = 0, 20/3

Hence, the answer.