Why is this capacitor useful?
A 600\mu F capacitor is connected in parallel to a circuit containing a 5.0\Omega coil of resistance. A current of 2.0*10^3 A is passed during 1.4*10^(-3) s
How do I explain why this capacitor is useful for providing the current for that amount of time?
A 600
How do I explain why this capacitor is useful for providing the current for that amount of time?
1 Answer
Current passes for
It is given that a current of
The usefulness of this charged capacitor is to act like a voltage source to provide given current to the circuit the during given time interval as shown below.
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en.wikipedia.org
Capacitor
:.V_C=V_R
=>Q/C=iR
wherei is the current flowing.
Reqriting and solving the differential equation we get for the discharge of capacitor
(dQ)/dt=-1/(RC)Q
Q(t)=Q_0e^(-t/(RC))
And for current in the circuit
|i(t)|=|(dQ)/dt|=(Q_0/(RC))e^(-t/(RC))=i_0e^(-t/(RC))
We see that the charge and current decay exponentially. Such heavy currents can be sustained only for a short duration which is shorter than