Question

How do you solve `2abs(y-3)+6 < 0`?

Answer 1

`y in O/`

Explanation:

`2|y+3|+6<0`
`|y+3|+3<0`
`|y+3|<-3`
So:
If `y<-3`
`-(y+3)<-3`
`-y-3<-3`
`y+3>3`
`cancel(y>0)` because of our domain.
If `y> -3`,
`y+3<-3`
`cancel(y<-6)` because of our domain.
So : `y in O/`
\0/ here's our answer !