Question

How to solve this derivative with steps please? `sin (xy) - (x^3)(y^2) = 0`

Answer 1

`y'=(3x^2y^2-ycos(xy))/(xcos(xy)-2x^3y)`

Explanation:

By the cahin rule we get
`cos(xy)(y+xy')-3x^2y^2-x^3*2y*y'=0`
solving for `y'`
`y'=(3x^2y^2-ycos(xy))/(xcos(xy)-2x^3y)`
for

`xcos(xy)-2x^3yne0`