How do you find the acceleration for the function #s(t)=-16t^2+100t +20# ?

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Answer 1 · 2018-06-04T18:32:42

# -32" unit."#

The velocity #v# of the particle travelling distance #s# in time #t# is given

by, #v=(ds)/dt#.

The acceleration #a# then is #a=(dv)/dt=(d^2s)/dt^2#.

#:. v=(ds)/dt=d/dt{s(t)}#

#=d/dt{-16t^2+100t+20}#

#=-16*2t+100#.

# rArr v=-32t+100#.

Then, #a=(dv)/dt=d/dt{-32t+100}=-32" unit."#