What Is #(x^3+x^2-5x+6)/(x+1)#? Help, Please?
1 Answer
Jun 4, 2018
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(x^2)(x+1)cancel(color(magenta)(-x^2))cancel(+x^2)-5x+6#
#=color(red)(x^2)(x+1)color(red)(-5)(x+1)color(magenta)(+5)+6#
#=color(red)(x^2)(x+1)color(red)(-5)(x+1)+11#
#"quotient "=color(red)(x^2-5)" remainder "=11#
#(x^3+x^2-5x+6)/(x+1)=x^2-5+11/(x+1)#
