How do you simplify #((4a^7b^4)/(8b^2))^3#?

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Answer 1 · 2018-06-05T13:13:30

#=(a^21b^6)/8#

As per the question, we have

#((4a^7b^4)/(8b^2))^3#

#=((cancel4a^7b^4)/(cancel8 2b^2))^3#

#=((a^7cancelb^2xxb^2)/(2cancelb^2))^3#

#=((a^7b^2)/(2))^3#

Now cubing these terms, we get

#(a^(7xx3)xxb^(2xx3))/2^3#

#= (a^21b^6)/8#

Hence, the answer.