How do you find # \frac { d y } { d x }# if #y = \sin 3x + \cos 2x#?

1 Answer
Jim G.
Jun 6, 2018

#dy/dx=3cos3x-2sin2x#

Explanation:

#"differentiate both terms using the "color(blue)"chain rule"#

#"given "y=f(g(x))" then"#

#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#

#dy/dx=cos3x xxd/dx(3x)-sin2x xxd/dx(2x)#

#color(white)(dy/dx)=3cos3x-2sin2x#

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