How do you write #(9x+6)(3x-2)# in standard quadratic form?

1 Answer
Jun 6, 2018

#27x^2-12#

Explanation:

Firstly, you need to know what standard quadratic form is. The standard quadratic form is #ax^2 + bx + c#.
Then, you expand the equation given to you:
#(9x+6)(3x-2)#
= #27x^2-18x+18x-12#
As you can see, your quadratic form has been satisfied.
Cancel out the #-18x+18x# since the sum would be zero.
Your answer would be:
#27x^2-12#