How do you differentiate #g(x) = (6x+9)(x^2-4)# using the product rule?
1 Answer
Jun 6, 2018
Explanation:
#"given "g(x)=f(x)h(x)" then"#
#g'(x)=f(x)h'(x)+h(x)f'(x)larrcolor(blue)"product rule"#
#f(x)=6x+9rArrf'(x)=6#
#h(x)=x^2-4rArrh'(x)=2x#
#rArrg'(x)=2x(6x+9)+6(x^2-4)#
#color(white)(rArrg'(x))=12x^2+18x+6x^2-24#
#color(white)(rArrg'(x))=18x^2+18x-24#
