How do you solve #4x ^ { 2} - 5= 95#?
1 Answer
Jun 7, 2018
Explanation:
#"isolate "4x^2" by adding 5 to both sides"#
#4x^2=95+5=100#
#"divide both sides by 4"#
#x^2=100/4=25#
#color(blue)"take the square root of both sides"#
#sqrt(x^2)=+-sqrt25larrcolor(blue)"note plus or minus"#
#rArrx=+-5#
