Question

How do you solve the system of equations:y=4, 3/5x+y=8?

When getting rid of the fraction, do you do this:
3/5x+y=8
5 5
3x+y=40

or:
3x+5y=40?

Answer 1

`(x,y) = (20/3, 4)`

Explanation:

First, to answer your equation, multiplying the whole equation ("getting rid of the fraction" `3/5x+y=8` by 5 would give you `3x+5y=40`

Now, for solving the system of equations:
`3x+5y=40`
`y=4`
Those are our two equations.
We can plug `y=4` (which is given) into the other equation to solve for x.
`3x+5(4)=40`
`3x+20=40`
`3x=20`
`x=20/3`
Because the y-value was given to us, we can conclude that `(x,y) = (20/3, 4)`