What is the limit of x to infinity of x^2-3/e^x?
1 Answer
Jun 8, 2018
Explanation:
We want to evaluate the limit
L=lim_(x->oo)(x^2-3)/e^x
Which is an indeterminate form
So we can apply L'Hôpital's rule
color(blue)(lim_(x->c)f(x)/g(x)=lim_(x->c)(f'(x))/(g'(x))
Thus
L=lim_(x->oo)(2x)/e^x
An indeterminate form
L=lim_(x->oo)(2)/e^x=0