How do you solve #5( x + 5) ^ { 1/ 3} = - 15#?

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Answer 1 · 2018-06-08T20:25:40

#-32#

#(x+5) wedge 1/3 = -3#

#x + 5 = -27#

Answer 2 · 2018-06-08T20:27:53

#x=-32#

#5( x + 5) ^ { 1/ 3} = - 15#

can be rewritten as:

#5root(3)(x+5)=-15#

#root(3)(x+5)=-3#

#(root(3)(x+5))^3=(-3)^3#

#x+5=-27#

#x=-32#