Question

Aaron has 21 coins that are nickels and dimes. If his total is $1.65 how many of each type of coin does he have?

Answer 1

Refer to the explanation.

Explanation:

Let `x` be the number of nickels and `y` be the number of dimes. Then we have the simultaneous equations:

`x+y=21`

`0.05x+0.1y=1.65`

The first equation becomes: `0.05x+0.05y=1.05`

Subtracting the second eqn. from the first, we get:

`0.05x+0.1y-0.05x+0.05y=1.65-1.05`

`0.05y=0.6`

`y=12`

`:.x+12=21`

`x=9`

So, he had `9` nickels and `12` dimes.