How do you solve #19- \frac { 5} { 2} x = 34#?

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Answer 1 · 2018-06-11T16:41:21

#x=-6#

The fraction might be what's bothering you here. Luckily, we can multiply all terms by #2# to get rid of it. We now have

#38-5x=68#

Since I did the same thing to both sides of this equation, I didn't change the value of this equation. Let's subtract #38# from both sides to get

#-5x=30#

And our last step would be to divide both sides by #-5# to get

#x=-6#

Hope this helps!

Answer 2 · 2018-06-11T16:49:34

#x=-6#

One possible way is to change to a decimal:

#5/2 rArr 2.5#

#therefore# #19-2.5x=34#

#-2.5x=15#

#x=15/-2.5=-6#

Alternate (although harder):

Change everything to a fraction:

#38/2-5/2x=68/2#

(multiply all numbers by #2# and divide by #2#)

#-5/2x=30/2#

#x=(30/2)/(-5/2)=-6#

Another alternate way:

Multiply all by #2#

#38-5x=68#

#-5x=30#

#x=30/-5=-6#