How do you turn a standard form to vertex form $y = x^{2} - 2 x + 1$ $y=x^2-2x+1$ ?

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How do you turn a standard form to vertex form $y = x^{2} - 2 x + 1$ $y=x^2-2x+1$ ?

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Answer 1 · 2018-06-12T01:25:49

${(x - 1)}^{2}$ $(x-1)^2$

Explanation:

$x^{2} - 2 x + 1 = x^{2} - 2 x + 1^{2}$ $x^2-2x+1=x^2-2x+1^2$
so $x^{2} - 2 x + 1 = {(x - 1)}^{2}$ $x^2-2x+1=(x-1)^2$ $0 \cdot 2 = 0$ $0*2=0$
$(x - 1)$ $(x-1)$ must be equal to $0$ $0$
so $x = 1$ $x= 1$

Answer 2 · 2018-06-12T11:11:29

complete the square

${(x - 1)}^{2} + 1 - 1$ $(x-1)^2+1-1$

${(x - 1)}^{2}$ $(x-1)^2$

Vertex (1,0)

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How do you turn a standard form to vertex form $y = x^{2} - 2 x + 1$ $y=x^2-2x+1$ ?

2 Answers

Explanation:

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Math

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How do you turn a standard form to vertex form y=x2−2x+1 y=x^2-2x+1?

2 Answers

Explanation:

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How do you turn a standard form to vertex form $y = x^{2} - 2 x + 1$ $y=x^2-2x+1$ ?