What is the force, in terms of Coulomb's constant, between two electrical charges of 6C and 16C that are 9m apart?

2 Answers
Jun 12, 2018

I get approximately 10.7k.

Explanation:

Coulomb's law states that:

F=kq1q2r2

where:

  • k is Coulomb's constant

  • q1,q2 are charges of the two charges in coulombs

  • r is the distance between the charges in meters

So, we get:

F=k6169

10.7k

Jun 12, 2018

F1.06521010N

Explanation:

Coulomb's Law with Coulomb's constant:

F=kQ1Q2r2

We will assume that the charges occur in a vacuum.

k=8.988109Nm2C2
Q1=6C
Q2=16C
r=9m

F=(8.988109)(6)(16)92

F1.06521010N