Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-6 C` and `-16 C` that are `9 m` apart?

Answer 1

I get approximately `10.7k`.

Explanation:

Coulomb's law states that:

`F=k(q_1q_2)/r^2`

where:

• `k` is Coulomb's constant

• `q_1,q_2` are charges of the two charges in coulombs

• `r` is the distance between the charges in meters

So, we get:

`F=k(-6*-16)/9`

`~~10.7k`

Answer 2

`F~~1.0652*10^10 N`

Explanation:

Coulomb's Law with Coulomb's constant:

`F=(kQ_1Q_2)/r^2`

We will assume that the charges occur in a vacuum.

`k= 8.988*10^9 (Nm^2)/C^2`
`Q_1=-6 C`
`Q_2=-16 C`
`r=9 m`

`F=(( 8.988*10^9)(-6)(-16))/9^2`

`F~~1.0652*10^10 N`